fs: simplify misleading code to remove ambiguity regarding ihold()/iput()

Because 'inode' is being initialised before checking if 'dentry' is negative
it looks like an extra iput() on 'inode' may happen since the ihold() is
done only if the dentry is *not* negative.  In reality this doesn't happen
because d_is_negative() is never true if ->d_inode is NULL.  This patch only
makes the code easier to understand, as I was initially mislead by it.

Signed-off-by: Luís Henriques <lhenriques@suse.de>
Link: https://lore.kernel.org/r/20230928152341.303-1-lhenriques@suse.de
Signed-off-by: Christian Brauner <brauner@kernel.org>
This commit is contained in:
Luís Henriques
2023-09-28 16:23:41 +01:00
committed by Christian Brauner
parent 85fadf89e5
commit 6036c5f131
+1 -3
View File
@@ -4367,11 +4367,9 @@ retry_deleg:
if (!IS_ERR(dentry)) {
/* Why not before? Because we want correct error value */
if (last.name[last.len])
if (last.name[last.len] || d_is_negative(dentry))
goto slashes;
inode = dentry->d_inode;
if (d_is_negative(dentry))
goto slashes;
ihold(inode);
error = security_path_unlink(&path, dentry);
if (error)