debugfs: remove return value of debugfs_create_bool()

No one checks the return value of debugfs_create_bool(), as it's not
needed, so make the return value void, so that no one tries to do so in
the future.

Link: https://lore.kernel.org/r/20210521184519.1356639-1-gregkh@linuxfoundation.org
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
This commit is contained in:
Greg Kroah-Hartman
2021-05-21 20:45:19 +02:00
parent 1be4ec2456
commit 393b06383f
3 changed files with 9 additions and 22 deletions
+3 -12
View File
@@ -846,20 +846,11 @@ static const struct file_operations fops_bool_wo = {
* This function creates a file in debugfs with the given name that
* contains the value of the variable @value. If the @mode variable is so
* set, it can be read from, and written to.
*
* This function will return a pointer to a dentry if it succeeds. This
* pointer must be passed to the debugfs_remove() function when the file is
* to be removed (no automatic cleanup happens if your module is unloaded,
* you are responsible here.) If an error occurs, ERR_PTR(-ERROR) will be
* returned.
*
* If debugfs is not enabled in the kernel, the value ERR_PTR(-ENODEV) will
* be returned.
*/
struct dentry *debugfs_create_bool(const char *name, umode_t mode,
struct dentry *parent, bool *value)
void debugfs_create_bool(const char *name, umode_t mode, struct dentry *parent,
bool *value)
{
return debugfs_create_mode_unsafe(name, mode, parent, value, &fops_bool,
debugfs_create_mode_unsafe(name, mode, parent, value, &fops_bool,
&fops_bool_ro, &fops_bool_wo);
}
EXPORT_SYMBOL_GPL(debugfs_create_bool);